84 lines
2.4 KiB
TypeScript
84 lines
2.4 KiB
TypeScript
import Path from "./common/path";
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/**
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* Copyright 2013-2019 GenieACS Inc.
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*
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* This file is part of GenieACS.
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*
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* GenieACS is free software: you can redistribute it and/or modify
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* it under the terms of the GNU Affero General Public License as
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* published by the Free Software Foundation, either version 3 of the
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* License, or (at your option) any later version.
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*
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* GenieACS is distributed in the hope that it will be useful,
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* but WITHOUT ANY WARRANTY; without even the implied warranty of
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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* GNU Affero General Public License for more details.
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*
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* You should have received a copy of the GNU Affero General Public License
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* along with GenieACS. If not, see <http://www.gnu.org/licenses/>.
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*/
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const WILDCARD_MULTIPLIER = 2;
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const UNDISCOVERED_DEPTH = 7;
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// Simple heuristic to estimate GPN count given a set of patterns to be
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// discovered. Used to decide whether to use nextLevel = false in GPN.
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// gpnPatterns is [pattern, flags]
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// pattern is a path (array)
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// flags is an int where its bits mark the segments in the pattern that
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// need refreshing. Leading 0s indicate that the pattern up to that
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// point has been discovered.
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export function estimateGpnCount(
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gpnPatterns: [Path, number][],
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depth: number = 0
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): number {
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const children: { [segment: string]: [Path, number][] } = {};
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const wildcardChildren: [Path, number][] = [];
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let wildcardDiscovered = false;
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let gpnCount = 0;
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for (const pattern of gpnPatterns) {
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const path = pattern[0];
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const flags = pattern[1] >> depth;
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const k = path.segments[depth] as string;
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if (!k) {
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if (flags & 1) gpnCount = 1;
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continue;
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}
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if (flags & 1) {
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gpnCount = 1;
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if (depth > UNDISCOVERED_DEPTH) continue;
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} else if (k === "*") {
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wildcardDiscovered = true;
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}
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if (k === "*") {
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wildcardChildren.push(pattern);
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} else {
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children[k] = children[k] || [];
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children[k].push(pattern);
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}
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}
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let wildcardGpnCount = 0;
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if (!wildcardDiscovered && wildcardChildren.length) {
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wildcardGpnCount +=
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estimateGpnCount(wildcardChildren, depth + 1) * WILDCARD_MULTIPLIER;
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}
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for (const k of Object.keys(children)) {
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const c = estimateGpnCount(children[k].concat(wildcardChildren), depth + 1);
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wildcardGpnCount -= c;
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gpnCount += c;
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}
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gpnCount += Math.max(0, wildcardGpnCount);
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return gpnCount;
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}
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